Ksp for CrOH3 is . What is the molar solubility of this salt in water? [2025]

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Q.
$K_{s p}$ for $C r {(O H)}_{3}$ is $1.6 \times 10^{- 30}$ . What is the molar solubility of this salt in water [2025]

1 $\sqrt[4]{\frac{1.6 \times 10^{- 30}}{27}}$

2 $\sqrt[5]{1.8 \times 10^{- 30}}$

3 $\frac{1.8 \times 10^{- 30}}{27}$

4 $\sqrt[2]{1.6 \times 10^{- 30}}$

Ans.
(1)

$C r {(O H)}_{3} ⇌ \underset{s}{C r^{3 +}} + \underset{3 s}{3 O} H^{-}$

$K_{s p} = [C r^{3 +}] {[O H^{-}]}^{3}$

$K_{s p} = s \times {(3 s)}^{3}$

$s = \sqrt[4]{\frac{K_{s p}}{27}} = \sqrt[4]{\frac{1.6 \times 10^{- 30}}{27}}$

Solution

Q.
$K_{s p}$ for $C r {(O H)}_{3}$ is $1.6 \times 10^{- 30}$ . What is the molar solubility of this salt in water [2025]

1 $\sqrt[4]{\frac{1.6 \times 10^{- 30}}{27}}$

2 $\sqrt[5]{1.8 \times 10^{- 30}}$

3 $\frac{1.8 \times 10^{- 30}}{27}$

4 $\sqrt[2]{1.6 \times 10^{- 30}}$

Ans.
(1)

$C r {(O H)}_{3} ⇌ \underset{s}{C r^{3 +}} + \underset{3 s}{3 O} H^{-}$

$K_{s p} = [C r^{3 +}] {[O H^{-}]}^{3}$

$K_{s p} = s \times {(3 s)}^{3}$

$s = \sqrt[4]{\frac{K_{s p}}{27}} = \sqrt[4]{\frac{1.6 \times 10^{- 30}}{27}}$

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Solution

Q. Ksp for Cr(OH)3 is 1.6×10-30. What is the molar solubility of this salt in water [2025]

1 1.6×10-30274

2 1.8×10-305

3 1.8×10-3027

4 1.6×10-302

Ans. (1) Cr(OH)3⇌Cr3+ s+3O3sH- Ksp=[Cr3+][OH-]3 Ksp=s×(3s)3 s=Ksp274 =1.6×10-30274

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Q.
$K_{s p}$ for $C r {(O H)}_{3}$ is $1.6 \times 10^{- 30}$ . What is the molar solubility of this salt in water [2025]

1 $\sqrt[4]{\frac{1.6 \times 10^{- 30}}{27}}$

2 $\sqrt[5]{1.8 \times 10^{- 30}}$

3 $\frac{1.8 \times 10^{- 30}}{27}$

4 $\sqrt[2]{1.6 \times 10^{- 30}}$

Ans.
(1)

$C r {(O H)}_{3} ⇌ \underset{s}{C r^{3 +}} + \underset{3 s}{3 O} H^{-}$

$K_{s p} = [C r^{3 +}] {[O H^{-}]}^{3}$

$K_{s p} = s \times {(3 s)}^{3}$

$s = \sqrt[4]{\frac{K_{s p}}{27}} = \sqrt[4]{\frac{1.6 \times 10^{- 30}}{27}}$