In Young’s double slit experiment, carried out with light of wavelength 5000 Å, the distance between the slits is 0.3 mm and the screen is at 200 cm from the slits. The central maximum is at x = 0 cm. The value of x for the third maxima is __________ mm.

Question

In Young’s double slit experiment, carried out with light of wavelength 5000 $Å$ , the distance between the slits is 0.3 mm and the screen is at 200 cm from the slits. The central maximum is at $x$ = 0 cm. The value of $x$ for the third maxima is __________ mm. [2024]

Smart Achievers · Accepted Answer

(10) $β = \frac{λ D}{d} = \frac{5 \times 10^{- 7} \times 2}{3 \times 10^{- 4}} = \frac{10 \times 10^{- 3}}{3} m$

$For 3^{rd} maxima y_{3} = 3 β = 10 \times 10^{- 3} m = 10 mm$

Solution

Q.
In Young’s double slit experiment, carried out with light of wavelength 5000 $Å$ , the distance between the slits is 0.3 mm and the screen is at 200 cm from the slits. The central maximum is at $x$ = 0 cm. The value of $x$ for the third maxima is __________ mm. [2024]

Ans.
(10) $β = \frac{λ D}{d} = \frac{5 \times 10^{- 7} \times 2}{3 \times 10^{- 4}} = \frac{10 \times 10^{- 3}}{3} m$

$For 3^{rd} maxima y_{3} = 3 β = 10 \times 10^{- 3} m = 10 mm$

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Solution

Q. In Young’s double slit experiment, carried out with light of wavelength 5000 Å, the distance between the slits is 0.3 mm and the screen is at 200 cm from the slits. The central maximum is at x = 0 cm. The value of x for the third maxima is __________ mm. [2024]

Ans. (10) β=λDd=5×10-7×23×10-4=10×10-33 m For 3rd maxima y3=3β=10×10-3 m=10 mm

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Q.
In Young’s double slit experiment, carried out with light of wavelength 5000 $Å$ , the distance between the slits is 0.3 mm and the screen is at 200 cm from the slits. The central maximum is at $x$ = 0 cm. The value of $x$ for the third maxima is __________ mm. [2024]

Ans.
(10) $β = \frac{λ D}{d} = \frac{5 \times 10^{- 7} \times 2}{3 \times 10^{- 4}} = \frac{10 \times 10^{- 3}}{3} m$

$For 3^{rd} maxima y_{3} = 3 β = 10 \times 10^{- 3} m = 10 mm$