In which case is number of molecules of water maximum? [2018]

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Solution

Q.
In which case is number of molecules of water maximum [2018]

1 18 mL of water

2 0.18 g of water

3 0.00224 L of water vapours at 1 atm and 273 K

4 $10^{- 3}$ mol of water

Ans.
(1)

(1)  Mass of water $= V \times d = 18 \times 1 = 18$ $g$

Molecules of water $= mole \times N_{A} = \frac{18}{18} N_{A} = N_{A}$

(2)  Molecules of water $= mole \times N_{A} = \frac{0.18}{18} N_{A} = 10^{- 2} N_{A}$

(3)  Moles of water $= \frac{0.00224}{22.4} = 10^{- 4}$

Molecules of water $= mole \times N_{A} = 10^{- 4} N_{A}$

(4)  Molecules of water $= mole \times N_{A} = 10^{- 3} N_{A}$

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