In this figure the resistance of the coil of galvanometer is . The emf of the cell is 4 V. The ratio of potential difference across and is [2023]

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Solution

Q.
In this figure the resistance of the coil of galvanometer $G$ is $2 Ω$ . The emf of the cell is 4 V. The ratio of potential difference across $C_{1}$ and $C_{2}$ is [2023]

1 $\frac{5}{4}$

2 $1$

3 $\frac{3}{4}$

4 $\frac{4}{5}$

Ans.
(4)

$At steady state, current in the circuit is$

$i = \frac{4 V}{6 + 2 + 8} = \frac{1}{4} A$

$Voltage across C_{1} is$

$V_{1} = V_{A C} = i (6 Ω + 2 Ω) = \frac{1}{4} \times 8 = 2 V$

$Voltage across C_{2} is$

$V_{2} = V_{B D} = i (2 Ω + 8 Ω) = \frac{1}{4} \times 10 = 2.5 V$

$\Rightarrow \frac{V_{1}}{V_{2}} = \frac{2}{2.5} = \frac{4}{5}$

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