In the given triangle (Right angled at C), DE ? BC, AB = 5 cm, AD = 2 cm and BC = 3 cm. Using BPT/Thales theorem:

Question

In the given triangle (Right angled at C), DE || BC, AB = 5 cm, AD = 2 cm and BC = 3 cm. Using BPT/Thales theorem:

(i) AE = 8/5 cm

(ii) AE = 1 cm

(iii) AC = 4 cm

(iv) AC = 3 cm

Choose the correct option from the following:

Smart Achievers · Accepted Answer

(1)

Given right angled triangle ABC, using Pythagoras theorem we have

$A B ² = A C ² + B C ² \Rightarrow 5 ² = A C ² + 9 \Rightarrow A C ² = 25 - 9 = 16 \Rightarrow A C = 4 c m, H e n c e (i i i) i s c o r r e c t . G i v e n D E ∥ B C, u \sin g B P T t h e o r e m, A D / A B = A E / A C \Rightarrow 2 / 5 = A E / 4 \Rightarrow A E = 8 / 5 c m, H e n c e (i) i s c o r r e c t .$

Solution

Q.
In the given triangle (Right angled at C), DE || BC, AB = 5 cm, AD = 2 cm and BC = 3 cm. Using BPT/Thales theorem:

(i) AE = 8/5 cm

(ii) AE = 1 cm

(iii) AC = 4 cm

(iv) AC = 3 cm

Choose the correct option from the following:

1 (i) and (iii) are correct.

2 (i) and (iv) are correct.

3 (ii) and (iii) are correct.

4 (ii) and (iv) are correct

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