Q.

In the given figure, a diode D is connected to an external resistance R=100Ω and an e.m.f. of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current in the circuit will be

1 20 mA  
2 35 mA  
3 30 mA  
4 40 mA  

Ans.

(3)

The potential difference across the resistance R is

         V=3.5 V-0.5 V=3 V

By Ohm’s law,

the current in the circuit is  

I=VR=3V100Ω=3×10-2A=30×10-3A=30 mA