In the given circuit, the voltage across load resistance (RL) is [2024]
(1)
(VB)Si=0.7V
(VB)Ge=0.3V
Voltage drop across both diodes =0.7+0.3=1V
So remaining 14 volts will drop across RL⇒
VL=2.5(1.5+2.5)×14=2.54×14 volt=8.75 volt