Q.

In the given circuit, the voltage across load resistance (RL) is          [2024]

1 8.75 V  
2 9.00 V  
3 8.50 V  
4 14.00 V  

Ans.

(1)

(VB)Si=0.7V

(VB)Ge=0.3V

Voltage drop across both diodes =0.7+0.3=1V

So remaining 14 volts will drop across RL

VL=2.5(1.5+2.5)×14=2.54×14 volt=8.75 volt