In the given circuit, the current flowing through the resistance 20 Ω is 0.3 A, while the ammeter reads 0.9 A. The value of R1 is ________ Ω. [2024]
(30)
Given, i1=0.3A,i1+i2+i3=0.9A
So, VAB=i1×20Ω=20×0.3V=6V
i2=6V15Ω=25A
i1+i2+i3=910A
310+25+i3=910 ⇒ i3=0.2A
⇒(0.2)R1=6
⇒R1=60.2=30Ω