In the given circuit, the breakdown voltage of the Zener diode is 3.0 V. What is the value of IZ [2024]
(2)
Breakdown voltage of the Zener diode, Vz=3V
Let potential at B=0V
Potential at E(VP)=10V and VC=VA=3V
I=10-31000=71000A and I1=32000A
Also, IZ+I1=I
Therefore, IZ=7-1.51000=5.5 mA