In the following circuit, the equivalent capacitance between terminal A and terminal B is [2024]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
In the following circuit, the equivalent capacitance between terminal A and terminal B is [2024]

1 2 $μ F$

2 1 $μ F$

3 0.5 $μ F$

4 4 $μ F$

Ans.
(1)

As, Wheatstone bridge is balanced, $\frac{C_{1}}{C_{2}} = \frac{C_{3}}{C_{4}}$ and $C_{5}$ becomes ineffective.

Capacitor $C_{1}$ and $C_{3}$ are in series.

$∴$ $C_{13} = \frac{C_{1} C_{3}}{C_{1} + C_{3}} = 1$ $μ F$

Similarly, capacitor, $C_{2}$ and $C_{4}$ are in series,

$∴$ $C_{24} = \frac{C_{2} C_{4}}{C_{2} + C_{4}} = 1$ $μ F$

Hence, equivalent capacitance between A and B is

$C_{13} + C_{24} = 2$ $μ F$

Want Us to Email you About Special Offers & Updates?