In sulphur estimation, 0.471 g of an organic compound gave 1.4439 g of barium sulphate. The percentage of sulphur in the compound is ________ (Nearest integer) (Given: Atomic mass Ba : 137u, S : 32u, O : 16u) [2023]

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Solution

Q.
In sulphur estimation, 0.471 g of an organic compound gave 1.4439 g of barium sulphate. The percentage of sulphur in the compound is ________ (Nearest integer)

(Given: Atomic mass Ba : 137u, S : 32u, O : 16u) [2023]

Ans.
(42)

$% sulphur = \frac{32}{233} \times \frac{{Weight of BaSO}_{4} formed}{Weight of organic compound} \times 100$

$= \frac{32}{233} \times \frac{1.4439}{0.471} \times 100 = 42.10$

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