In Carius method for estimation of halogens, 180 mg of an organic compound produced 143.5 mg of AgCl. The percentage composition of chlorine in the compound is ______ %. (Given: molar mass in g of Ag : 108, Cl : 35.5) [2025]

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Solution

Q.
In Carius method for estimation of halogens, 180 mg of an organic compound produced 143.5 mg of AgCl. The percentage composition of chlorine in the compound is ______ %.

(Given: molar mass in g ${mol}^{- 1}$ of Ag : 108, Cl : 35.5) [2025]

Ans.
(20)

$Moles of Cl = Moles of AgCl = \frac{Mass of AgCl}{Molar mass of AgCl}$

$= \frac{143.5 mg}{143.5 g} = \frac{143.5 \times 10^{- 3}}{143.5} = 10^{- 3} mol$

$Mass of Cl = Moles of Cl \times Molar mass of Cl$

$= 10^{- 3} mol \times 35.5 {g mol}^{- 1} = 0.0355 g$

$Mass of organic compound = 180 mg = 0.180 g$

$Mass percent of Cl = \frac{Mass of Cl}{Mass of organic compound} \times 100$

$= \frac{0.0355}{0.180} \times 100 = 19.72 % \approx 20 %$

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