In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of singl

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern [2015]

1 0.5 mm

2 0.02 mm

3 0.2 mm

4 0.1 mm

Ans.
(3)

For double slit experiment,

$d = 1$ $mm = 1 \times 10^{- 3}$ $m, D = 1$ $m, λ = 500 \times 10^{- 9}$ $m$

$Fringe width β = \frac{D λ}{d}$

$Width of central maxima in a single slit = \frac{2 λ D}{a}$

As per question, width of central maxima of single slit pattern = width of 10 maxima of double slit pattern

$\frac{2 λ D}{a} = 10 (\frac{λ D}{d}) or a = \frac{2 d}{10} = \frac{2 \times 10^{- 3}}{10} = 0.2 \times 10^{- 3} m = 0.2$ $mm$

Want Us to Email you About Special Offers & Updates?