Q.

In a coil, the current changes from -2A to +2A in 0.2 s and induces an emf 0.1 V. The self-inductance of the coil is:               [2024]

1 4 mH  
2 5 mH  
3 2.5 mH  
4 1 MH  

Ans.

(2)     

           (Emf)induced=-Ldidt

           In magnitude form,

           |Emfind|=|(-)Ldidt|

           0.1=(L)[+2-(-2)]0.2L=0.1×0.24=5mH