If the wavelength of the first member of Lyman series of hydrogen is . The wavelength of the second member will be

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Solution

Q.
If the wavelength of the first member of Lyman series of hydrogen is $λ$ . The wavelength of the second member will be [2024]

1 $\frac{5}{27} λ$

2 $\frac{27}{32} λ$

3 $\frac{32}{27} λ$

4 $\frac{27}{5} λ$

Ans.
(2)

$\frac{1}{λ} = \frac{13.6 z^{2}}{h c} [\frac{1}{1^{2}} - \frac{1}{2^{2}}]$ ...(i)

$\frac{1}{λ^{'}} = \frac{13.6 z^{2}}{h c} [\frac{1}{1^{2}} - \frac{1}{3^{2}}]$ ...(ii)

$O n d i v i d i n g (i) a n d (i i) λ^{'} = \frac{27}{32} λ$

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