If the system of equations
x+y+az=b
2x+5y+2z=6
x+2y+3z=3
has infinitely many solutions, then 2a+3b is equal to [2023]
(4)
Given system of equations are
For infinitely many solutions, Δ=0, Δ1=0, Δ2=0, Δ3=0
Δ=|11a252123|=0⇒1(15-4)-1(6-2)+a(4-5)=0
⇒11-4-a=0⇒a=7
Δ1=|b1a652323|=0
⇒b(15-4)-1(18-6)+a(12-15)=0
⇒11b-12+7(-3)=0⇒b=3311=3
∴ 2a+3b=2(7)+3(3)=23