Q.

If the system of equations

x+y+az=b

2x+5y+2z=6

x+2y+3z=3

has infinitely many solutions, then 2a+3b is equal to               [2023]

1 20  
2 25  
3 28  
4 23  

Ans.

(4)

Given system of equations are

x+y+az=b

2x+5y+2z=6

x+2y+3z=3

For infinitely many solutions, Δ=0, Δ1=0, Δ2=0, Δ3=0

Δ=|11a252123|=01(15-4)-1(6-2)+a(4-5)=0

11-4-a=0a=7

Δ1=|b1a652323|=0

b(15-4)-1(18-6)+a(12-15)=0

11b-12+7(-3)=0b=3311=3

  2a+3b=2(7)+3(3)=23