Q.

If the system of equations

x+2y+3z=3

4x+3y-4z=4

8x+4y-λz=9+μ

has infinitely many solutions, then the ordered pair (λ,μ) is equal to               [2023]

1 (725,-215)  
2 (725,215)  
3 (-725,-215)  
4 (-725,215)  

Ans.

(1)

x+2y+3z=3;  4x+3y-4z=4;  8x+4y-λz=9+μ

For infinite many solutions, Δ=0 and Δx=0

Δ=|12343-484-λ|=0

1(-3λ+16)-2(-4λ+32)+3(16-24)=0

16-3λ+8λ-64-24=05λ=72

   λ=725

Δx=|32343-49+μ4-λ|=0

3(-3λ+16)-2(-4λ+36+4μ)+3(16-27-3μ)=0

-9λ+48+8λ-72-8μ-33-9μ=0

-λ-17μ=57-17μ=57+λ

   -μ=57+72517μ=-35785=-215

Thus, (λ,μ)(725,-215)