Q.

If the system of equations

(λ1)x+(λ4)y+λz=5

λx+(λ1)y+(λ4)z=7

(λ+1)x+(λ+2)y(λ+2)z=9

has infinitely many solutions, then λ2+λ is equal to          [2025]

1 20  
2 12  
3 6  
4 10  

Ans.

(2)

For infinitely many solutions,

D=|(λ1)(λ4)λλ(λ1)(λ4)(λ+1)(λ+2)(λ+2)|=0          ... (i)

On solving (i) along column (1), we get

2λ25λ3=0

 (2λ+1)(λ3)=0

 λ=3 or 12          ... (ii)

D2=0 |(λ1)5λλ7(λ4)(λ+1)9(λ+2)|=0

 2λ213λ+21=0

 (2λ7)(λ3)=0

 λ=7/2 or λ=3          ... (iii)

Thus, λ=3          (From (ii) and (iii))

  λ2+λ=(3)2+3=9+3=12.