Q.

If the system of equations

2x – y + z = 4

5x+λy+3z=12

100x–47y+μz=212

has infinitely many solutions, then μ–2λ is equal to          [2025]

1 55  
2 59  
3 56  
4 57  

Ans.

(4)

As the given system of equations has infinitely many solutions, then

△=△1=△2=△3=0

△2=|2415123100212μ|=0

⇒ 2(12μ–636)–4(5μ–300)+1(1060–1200)=0

⇒ 4μ–212=0

⇒ μ=53

△3=|2–145λ12100–47212|=0

⇒ 2(212λ+564)+1(1060–1200)+4(–235–100λ)=0

⇒ 24λ+48=0 ⇒ λ=–2

∴  μ–2λ=53–2(–2)=57.