Q.

If the system of equations

2x+λy+3z=5

3x+2yz=7

4x+5y+μz=9

has infinitely many solutions, then (λ2+μ2) is equal to:          [2025]

1 22  
2 18  
3 26  
4 30  

Ans.

(3)

For infinitely man solutions, we have =1=2=3=0

Now, =|2λ332145μ|=0

 2(2μ+5)λ(3μ+4)+3(158)=0

 4μ+103λμ4λ+21=0

 4μ4λ3λμ+31=0           ... (i)

Now, 2=|25337149μ|=0

 2(7μ+9)5(3μ+4)+3(2728)

 14μ+1815μ203=0

 μ+1823=0  μ=5

Substituting the value of μ in (i), we get

   204λ+15λ+31=0

 11λ+11=0  λ=1

  λ2+μ2=(1)2+(5)2=26.