If the sum of the first four terms of an A.P. is 6 and the sum of its first six terms is 4, then the sum of its first twelve terms is [2026]
(4)
Sum of first 4 terms S4=6
42(2a+3d)=6⇒2a+3d=3 ...(1)
Sum of first 6 terms S6=4
62(2a+5d)=4⇒2a+5d=43 ...(2)
eq. (2) - eq. (1)
(2a+5d)-(2a+3d)=43-3
⇒d=-56
∴ 2a+3(-56)=3⇒a=114
S12=122{2(114)+(12-1)(-56)}
S12=6(-226)=-22