Q.

If the solution curve of the differential equation (y-2logex)dx+(xlogex2)dy=0, x>1 passes through the points (e,43) and (e4, α), then α is equal to ____ .    [2023]


Ans.

(3)

Given differential equation is (y-2logex)dx+(xlogex2)dy=0

⇒dydx=2logex-yxlogex2

⇒dydx+(1xlogex2)y=2logex2xlogex=1x

This is a linear differential equation of the type dydx+Py=Q

Here, P=1xlogex2, Q=1x

I.F.=e∫P dx=e∫12xlogexdx=logex

Solution of the differential equation is

      ylogex=∫1x·logex dx

⇒ylogex=23(logex)3/2+c  ⋯(i)

Now, put (e,43) in (i), we get 43=23+c ⇒ c=23

Now, put x=e4, y=α, c=23 in (i), we get

     αlogee4=23(logee4)3/2+23

⇒α×2=23×8+23⇒α=83+13=3