Q.

If the rate constant for a first order reaction is k, the time (t) required for the completion of 99% of the reaction is given by              [2019]

1 t=2.303/k  
2 t=0.693/k  
3 t=6.909/k  
4 t=4.606/k   

Ans.

(4)

For 1st order reaction,  

t=2.303klogaa-x=2.303klog100100-99

=2.303klog102=2.303k×2×log10=4.606k