If the molar conductivity of a 0.050 mol solution of a monobasic weak acid is 90 S , its extent (degree) of dissociation will be [2025]

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Solution

Q.
If the molar conductivity $(Λ_{m})$ of a 0.050 mol $L^{- 1}$ solution of a monobasic weak acid is 90 S ${cm}^{2}$ ${mol}^{- 1}$ , its extent (degree) of dissociation will be

$[Assume Λ_{+}^{\circ} = 349.6 {S cm}^{2} {mol}^{- 1} and Λ_{-}^{\circ} = 50.4 {S cm}^{2} {mol}^{- 1}]$ [2025]

1 0.225

2 0.215

3 0.115

4 0.125

Ans.
(1)

Given: Concentration of solution = 0.050 mol $L^{- 1}$

$Λ_{m} = 90 {S cm}^{2} {mol}^{- 1}$

$Λ_{m}^{o} = Λ_{+}^{o} + Λ_{-}^{o}$

$= 349.6 + 50.4 = 400 {S cm}^{2} {mol}^{- 1}$

$α = \frac{Λ_{m}}{Λ_{m}^{o}} = \frac{90}{400} = 0.225$

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