If the mirror image of the point P(3, 4, 9) in the line x-13=y+12=z-21 is (α,β,γ), then 14(α+β+γ) is : [2024]
(4)
Given equation of line is
x–13=y+12=z–21=λ (say)
∴ Any point on line, say m=(3λ+1, 2λ–1, λ+2)
Now, d.r.'s of PM=<3λ–2, 2λ–5, λ–7> and d.r.'s of given line = <3, 2, 1> ∵ PM⊥line
∴ 3(3λ–2)+2(2λ–5)+1(λ–7)=0
⇒ 14λ=23 ⇒ λ=2314
Now, M is the mid point of P(3, 4, 9) and Q(α,β,γ)
∴ 8314=3+α2 ⇒ α=627 ⇒ 167=4+β2 ⇒ β=47
and 5114=9+γ2 ⇒ γ=–127
So, 14(α+β+γ)=14×547=108.