If the line 2–x3=3y–24λ+1=4–z makes a right angle with the line x+33μ=1–2y6=5–z7, then 4λ+9μ is equal to : [2024]
(2)
We have lines 2–x3=3y–24λ+1=4–z and x+33μ=1–2y6=5–z7 are perpendicular.
i.e., x–2–3=y–2/34λ+13=z–4–1 and x–(–3)3μ=y–1/2–62=z–5–7 are perpendicular.
⇒–3(3μ)+4λ+13(–3)+(–1)(–7)=0
⇒–9μ–4λ–1+7=0
⇒–9μ–4λ+6=0 ⇒ 4λ+9μ=6.