If the image of the point (4, 4, 3) in the line x–12=y–21=z–13 is (α,β,γ), then α+β+γ is equal to [2025]
(1)
Let x–12=y–21=z–13=λ
⇒ M≡(2λ+1,λ+2,3λ+1)
PM→=(2λ–3)i^+(λ–2)j^+(3λ–2)k^
Since, PM→ is perpendicular to the given line
∴ 2(2λ–3)+1(λ–2)+3(3λ–2)=0
⇒ λ=1
∴ The coordinates of point M is (3, 3, 4).
Let Q be the image of the point P. Then, M be the mid-point of PQ.
∴ (4+α2,4+β2,3+γ2)≡(3,3,4)
⇒ α=2,β=2,γ=5 ∴ α+β+γ=9