Q.

If the function f(x)=2x39ax2+12a2x+1, where a > 0, attains its local maximum and local minimum values at p and q, respectively, such that p2=q, then f(3) is equal to :          [2025]

1 55  
2 10  
3 37  
4 23  

Ans.

(3)

We have, f(x)=2x39ax2+12a2x+1

 f'(x)=6x218ax+12a2

 f(x)=6(x23ax+2a2)=6(xa)(x2a)

 f'(x)=0  6(xa)(x2a)=0  x=a, 2a

Now, f''(x)=6(2x3a)

           f''(a)=6(2a3a)=6a<0 

   x = a is point of maxima          { a > 0}

            f''(2a)=6(4a3a)=6a>0 

   x = 2a is a point of minima

So, p = a and q = 2a.

Given, p2=q  a2=2a  a=2

Now, f(x)=2x39ax2+12a2x+1

            f(3) = 54 – 162 + 144 + 1 = 37.