Q.

If the equation a(bc)x2+b(ca)x+c(ab)=0 has equal roots, where a + c = 15 and b=365, then a2+c2 is equal to __________.          [2025]


Ans.

(117)

Since, a(bc)x2+b(ca)x+c(ab)=0 has equal roots

Put x = 1 in given equation.

   abac + bcab + acbc = 0

   Both roots of the equation is 1.

  1+1=b(ca)a(bc)

 2ab2ac=bc+ab

 2ac=bc+ab  2ac=b(a+c)

 2ac=365×15=108

Also, a + c = 15          [Given]

  a2+c2+2ac=225

 a2+c2=225108  a2+c2= 117.