Q.

If the domain of the function log5(18x–x2–77) is (α,β) and the domain of the function log(x–1)(2x2+3x–2x2–3x–4) is (γ,δ), then α2+β2+γ2 is equal to :          [2025]

1 195  
2 174  
3 186  
4 179  

Ans.

(3)

Let f1(x)=log5(18x–x2–77)

∴  18x–x2–77>0

⇒ x2–18x+77<0

⇒ (x–11)(x–7)<0

⇒ x∈(7,11)    ∴  α=7, β=11

Also, let f2(x)=log(x–1)(2x2+3x–2x2–3x–4)

∴  x–1>0 ⇒x>1, x–1≠1 ⇒ x≠2,

2x2+3x–2x2–3x–4>0 ⇒ (2x–1)(x+2)(x–4)(x+1)>0

⇒ x∈(4,∞)         ∴  γ=4

Now, α2+β2+γ2 = 49 + 121 + 16 = 186.