If the degree of dissociation of aqueous solution of weak monobasic acid is determined to be 0.3, then the observed freezing point will be _______% higher than the expected/theoretical freezing point. (Nearest integer) [2023]

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Solution

Q.
If the degree of dissociation of aqueous solution of weak monobasic acid is determined to be 0.3, then the observed freezing point will be _______% higher than the expected/theoretical freezing point. (Nearest integer) [2023]

Ans.
(30)

For monobasic acid, $n = 2$

$i = 1 + (n - 1) α = 1 + (2 - 1) \times 0.3 = 1.3$

$% increase = \frac{{(Δ T_{f})}_{_{obs}} - {(Δ T_{f})}_{cal}}{{(Δ T_{f})}_{cal}} \times 100$

$= \frac{i \times K_{f} \times m - K_{f} \times m}{K_{f} \times m} \times 100$

$= (i - 1) \times 100 = 0.3 \times 100 = 30 %$

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