Q.

If the area of the region {(x,y):1+x2≤y≤min {x+7,11–3x}} is A, then 3A is equal to          [2025]

1 47  
2 49  
3 50  
4 46  

Ans.

(3)

A=∫–21(x+7–x2–1)dx+∫12(11–3x–x2–1)dx

=[x22+6x–x33]–21+[10x–3x22–x33]12

=503 ⇒ 3A=50.