If the area of the region {(x,y):1+x2≤y≤min {x+7,11–3x}} is A, then 3A is equal to [2025]
(3)
A=∫–21(x+7–x2–1)dx+∫12(11–3x–x2–1)dx
=[x22+6x–x33]–21+[10x–3x22–x33]12
=503 ⇒ 3A=50.