If S(x)=(1+x)+2(1+x)2+3(1+x)3+…+60(1+x)60, x≠0 and (60)2S(60)=a(b)b+b, where a,b∈N, then (a+b) is equal to _______. [2024]
(3660)
=(1+x)((1+x)60-1)1+x-1-60(1+x)61
⇒x2S(x)=60x·(1+x)61-(1+x)((1+x)60-1)
For x=60, we have
(60)2S(60)=3600(61)61-61((61)60-1)
=(61)61[3600-1]+61=3599(61)61+61
⇒a=3599, b=61
∴a+b=3599+61=3660