Q.

If mass is written as m=kcPG-1/2h1/2 then the value of P will be (Constants have their usual meaning with k a dimensionless constant)         [2024]

1 1/2  
2 1/3  
3 2  
4 - 1/3  

Ans.

(1)  

        m=KCPG-1/2h1/2                                ...(1)

       G=Fr2m1·m2=MLT-2·L2M2=[M-1L3T-2]

        Now using (1)

        [M]=[LT-1]P [M-1L3T-2]-1/2 [ML2T-1]1/2

        Compare the dimension of T from L.H.S and R.H.S then

        -P+12=0P=12