If it takes 520 turns to make

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Solution

Q.
If it takes 520 turns to make a solenoid that is 40 cm long with a radius of 1.2 m that carries a current of 6 A, then determine the magnetic field inside the solenoid

1 $7.2 \times 10^{- 3} T$

2 $9.8 \times 10^{- 3} T$

3 $8.4 \times 10^{- 4} T$

4 $10.2 \times 10^{- 4} T$

Ans.
(2)

Given,
I=6 A, L=40 cm=0.4 m, r=1.2 m, N=520

We know that, $B = \frac{μ_{0} N I}{L}$

On substituting the values in above formula:

$B = \frac{(4 π \times 10^{- 7} \times 520 \times 6)}{0.4} = \frac{(4 \times 3.14 \times 10^{- 7} \times 520 \times 6)}{0.4} = 97968 \times 10^{- 7} = 9.8 \times 10^{- 3} T$

The magnetic field inside the solenoid is

$B = 9.8 \times 10^{- 3} T$

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