If f(x)=x3-x2f'(1)+xf''(2)-f'''(3), x∈R, then [2023]
(1)
Given, f(x)=x3-x2f'(1)+xf''(2)-f'''(3)
f'(x)=3x2-2xf'(1)+f''(2) ...(i)
f''(x)=6x-2f'(1) ...(ii)
f'''(x)=6⇒f'''(3)=6 ...(iii)
From (iii),
f''(2)=12-2f'(1) ...(iv)
From (ii),
f'(1)=3(1)2-2f'(1)+f''(2)
⇒f''(2)=3f'(1)-3 ...(v)
⇒12-2f'(1)=3f'(1)-3
⇒f'(1)=3; f''(2)=12-6=6 and f'(1)=3
f(x)=x3-3x2+6x-6⇒f(0)=-6
f(1)=-2, f(2)=2, f(3)=12
∴ 2f(0)-f(1)+f(3)=2=f(2)