If f(x)=x2+g'(1)x+g''(2) and g(x)=f(1)x2+xf'(x)+f''(x), then the value of f(4)-g(4) is equal to [2023]
(14)
Let g'(1)=A
g''(2)=B, f(x)=x2+Ax+B, f(1)=A+B+1
f'(x)=2x+A, f''(x)=2,
g(x)=(A+B+1)x2+x(2x+A)+2
⇒g(x)=x2(A+B+3)+Ax+2
g'(x)=2x(A+B+3)+A, g'(1)=A
⇒2(A+B+3)+A=A
A+B=-3 ...(i)
g''(x)=2(A+B+3), g''(2)=B
⇒2(A+B+3)=B
⇒2A+B=-6 ...(ii)
From (i) and (ii): A=-3, B=0
f(x)=x2-3x, f(4)=16-12=4
g(x)-3x+2, g(4)=-12+2=-10 f(4)-g(4)=4-(-10)=14