If E and G respectively denote energy and gravitational constant, then has the dimensions of [2021]

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Q.
If E and G respectively denote energy and gravitational constant, then $\frac{E}{G}$ has the dimensions of [2021]

1 $[M^{2}] [L^{- 2}] [T^{- 1}]$

2 $[M^{2}] [L^{- 1}] [T^{0}]$

3 $[M] [L^{- 1}] [T^{- 1}]$

4 $[M] [L^{0}] [T^{0}]$

Ans.
(2)

Dimensions of energy $[E] = [M L^{2} T^{- 2}]$

Dimensions of gravitational constant $[G] = [M^{- 1} L^{3} T^{- 2}]$

So, the dimensions of $[\frac{E}{G}] = \frac{[M L^{2} T^{- 2}]}{[M^{- 1} L^{3} T^{- 2}]} = [M^{2} L^{- 1} T^{0}] = [M^{2}] [L^{- 1}] [T^{0}]$

Solution

Q.
If E and G respectively denote energy and gravitational constant, then $\frac{E}{G}$ has the dimensions of [2021]

1 $[M^{2}] [L^{- 2}] [T^{- 1}]$

2 $[M^{2}] [L^{- 1}] [T^{0}]$

3 $[M] [L^{- 1}] [T^{- 1}]$

4 $[M] [L^{0}] [T^{0}]$

Ans.
(2)

Dimensions of energy $[E] = [M L^{2} T^{- 2}]$

Dimensions of gravitational constant $[G] = [M^{- 1} L^{3} T^{- 2}]$

So, the dimensions of $[\frac{E}{G}] = \frac{[M L^{2} T^{- 2}]}{[M^{- 1} L^{3} T^{- 2}]} = [M^{2} L^{- 1} T^{0}] = [M^{2}] [L^{- 1}] [T^{0}]$

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Solution

Q. If E and G respectively denote energy and gravitational constant, then EG has the dimensions of [2021]

1 [M2][L-2][T-1]

2 [M2][L-1][T0]

3 [M][L-1][T-1]

4 [M][L0][T0]

Ans. (2) Dimensions of energy [E]=[ML2T-2] Dimensions of gravitational constant [G]=[M-1L3T-2] So, the dimensions of [EG]=[ML2T-2][M-1L3T-2]=[M2L-1T0]=[M2][L-1][T0]

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Q.
If E and G respectively denote energy and gravitational constant, then $\frac{E}{G}$ has the dimensions of [2021]

1 $[M^{2}] [L^{- 2}] [T^{- 1}]$

2 $[M^{2}] [L^{- 1}] [T^{0}]$

3 $[M] [L^{- 1}] [T^{- 1}]$

4 $[M] [L^{0}] [T^{0}]$

Ans.
(2)

Dimensions of energy $[E] = [M L^{2} T^{- 2}]$

Dimensions of gravitational constant $[G] = [M^{- 1} L^{3} T^{- 2}]$

So, the dimensions of $[\frac{E}{G}] = \frac{[M L^{2} T^{- 2}]}{[M^{- 1} L^{3} T^{- 2}]} = [M^{2} L^{- 1} T^{0}] = [M^{2}] [L^{- 1}] [T^{0}]$