If Avogadro number is changed from 6.022 × to 6.022 × , this would change [2015]

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Q.
If Avogadro number $N_{A},$ is changed from 6.022 × $10^{23}$ ${mol}^{- 1}$ to 6.022 × $10^{20}$ ${mol}^{- 1}$ , this would change [2015]

1 the mass of one mole of carbon

2 the ratio of chemical species to each other in a balanced equation

3 the ratio of elements to each other in a compound

4 the definition of mass in units of grams.

Ans.
(1)

Mass of 1 mol $(6.022 \times 10^{23} atoms)$ of carbon = 12 g

If Avogadro number is changed to $6.022 \times 10^{20}$ atoms, then mass of 1 mol of carbon

$= \frac{12 \times 6.022 \times 10^{20}}{6.022 \times 10^{23}} = 12 \times 10^{- 3}$ $g$

Solution

Q.
If Avogadro number $N_{A},$ is changed from 6.022 × $10^{23}$ ${mol}^{- 1}$ to 6.022 × $10^{20}$ ${mol}^{- 1}$ , this would change [2015]

1 the mass of one mole of carbon

2 the ratio of chemical species to each other in a balanced equation

3 the ratio of elements to each other in a compound

4 the definition of mass in units of grams.

Ans.
(1)

Mass of 1 mol $(6.022 \times 10^{23} atoms)$ of carbon = 12 g

If Avogadro number is changed to $6.022 \times 10^{20}$ atoms, then mass of 1 mol of carbon

$= \frac{12 \times 6.022 \times 10^{20}}{6.022 \times 10^{23}} = 12 \times 10^{- 3}$ $g$

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Solution

Q. If Avogadro number NA, is changed from 6.022 × 1023 mol-1 to 6.022 × 1020 mol-1, this would change [2015]

1 the mass of one mole of carbon

2 the ratio of chemical species to each other in a balanced equation

3 the ratio of elements to each other in a compound

4 the definition of mass in units of grams.

Ans. (1) Mass of 1 mol (6.022×1023 atoms) of carbon = 12 g If Avogadro number is changed to 6.022×1020 atoms, then mass of 1 mol of carbon =12×6.022×10206.022×1023=12×10-3g

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Q.
If Avogadro number $N_{A},$ is changed from 6.022 × $10^{23}$ ${mol}^{- 1}$ to 6.022 × $10^{20}$ ${mol}^{- 1}$ , this would change [2015]

Ans.
(1)

Mass of 1 mol $(6.022 \times 10^{23} atoms)$ of carbon = 12 g

If Avogadro number is changed to $6.022 \times 10^{20}$ atoms, then mass of 1 mol of carbon

$= \frac{12 \times 6.022 \times 10^{20}}{6.022 \times 10^{23}} = 12 \times 10^{- 3}$ $g$