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Solution


Q.

If a pole 6 m high casts a shadow 23m long on the ground, then Sun’s elevation is:
 
1 60°  
2 45°  
3 30°  
4 90°  

Ans.

(1)

Let AB be the pole of height 6 m. Let θ be the angle of elevation of Sun and BC be the shadow of the pole. Then,

∠ACB = θ, AB = 6 m and BC = 2√3mIn △ABC, right angled at B, 

tan C=AB/BC⇒ tan θ=6/2√3=√3

⇒tan θ=tan 60∘⇒θ=60∘