If a→=i^+2k^, b→=i^+j^+k^, c→=7i^-3j^+4k^, r→×b→+b→×c→=0→ and r→·a→=0. Then r→·c→ is equal to [2023]
(1)
a→=i^+0j^+2k^
b→=i^+j^+k^; c→=7i^-3j^+4k^
and r→×b→+b→×c→=0 (given)
⇒r→×b→-c→×b→=0 (∵a→×b→=-b→×a→)
⇒(r→-c→)×b→=0 ⇒r→-c→=λb→⇒r→=c→+λb→
and r→·a→=0 is also given
⇒c→·a→+λ b→·a→=0 or λ=-c→·a→b→·a→
Now r→·c→=(c→+λb→)·c→
=[c→-c→·a→b→·a→b→]·c→=|c→|2-(c→·a→b→·a→)(b→·c→)
=74-[153]8=74-40=34