If a function f satisfies f(m+n)=f(m)+f(n) for all m, n∈N and f(1)=1, then the largest natural number λ such that ∑k=12022f(λ+k)≤(2022)2 is equal to ___________ . [2024]
(1010)
We have, f(m+n)=f(m)+f(n)
So, f(x)=kx
∵ f(1)=1⇒k=1
Hence, f(x)=x
Now, ∑k=12022f(λ+k)=∑k=12022(λ+k)
=λ+λ+...+λ⏟2022+(1+2+....+2022)
=2022λ+2022×20232≤(2022)2 (Given)
⇒λ≤20212
So, largest λ=1010