If a→,b→,c→ are three non-zero vectors and n^ is a unit vector perpendicular to c→ such that a→=αb→-n^,(α≠0) and b→·c→=12, then |c→×(a→×b→)| is equal to [2023]
(4)
We have, |n^|=1
Given, n^⊥c→, a→=αb→-n^ and b→·c→=12
Now, a→×b→=(αb→-n^)×b→=- n^×b→ ∴ c→×(a→×b→)=c→×(-n^×b→)
=(c→·b→)(-n^)-{c→·(-n^)}b→=-12n^+(0)b→=-12n^
∴ |c→×(a→×b→)|=12