If A=[2335], then the determinant of the matrix (A2025-3A2024+A2023) is [2026]
(1)
A=[2335]⇒ A2=[13212134]
|A2025-3A2024+A2023|
=|A2023(A2-3A+I)|
=|A|2023|A2-3A+I|
=1·|8121220|=160-144=16