Q.

If π2≤x≤3π4, then cos–1(1213cosx+513sinx) is equal to          [2025]

1 x–tan–1512  
2 x+tan–1512  
3 x+tan–145  
4 x–tan–143  

Ans.

(1)

Given, π2≤x≤3π4

Let cosα=1213        [∴ cos–1(1213cosx+513sinx)]

=cos–1(cosx cosα+sinx sinα)=cos–1(cos(x–α))=x–α

=x–tan–1(512)