If 1 mM solution of ethylamine produces pH = 9, then the ionization constant (Kb) of ethylamine is 10-x. The value of x is ______ (nearest integer).
[The degree of ionization of ethylamine can be neglected with respect to unity.] [2025]
(7)
C2H5NH2(aq)+H2O⇌C2H5NH3+(aq)+OH-(aq)t=010-3 Mexcess00t=∞10-3(1-α)10-3αM10-3αM≃10-3 M
pOH=14-pH=14-9=5
Thus [OH]-=10-5 M
Also, [C2H5NH3+]=[OH]-=10-5 M
Kb=[OH]-[C2H5NH3+][C2H5NH2]=10-5×10-510-3=10-7