Q.

If 1 mM solution of ethylamine produces pH = 9, then the ionization constant (Kb) of ethylamine is 10-x. The value of x is ______ (nearest integer).

[The degree of ionization of ethylamine can be neglected with respect to unity.]                      [2025]


Ans.

(7)

C2H5NH2(aq)+H2OC2H5NH3+(aq)+OH-(aq)t=010-3Mexcess00t=10-3(1-α)10-3αM10-3αM10-3M

pOH=14-pH=14-9=5 

Thus [OH]-=10-5M

Also, [C2H5NH3+]=[OH]-=10-5M

Kb=[OH]-[C2H5NH3+][C2H5NH2]=10-5×10-510-3=10-7