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Solution


Q.

Identify correct conversion during acidic hydrolysis from the following:

(A) Starch gives galactose.
(B) Cane sugar gives equal amount of glucose and fructose.
(C) Milk sugar gives glucose and galactose.
(D) Amylopectin gives glucose and fructose.
(E) Amylose gives only glucose.

Choose the correct answer from the options given below:                  [2025]
1 (B), (C) and (E) only  
2 (A), (B) and (C) only  
3 (C), (D) and (E) only  
4 (B), (C) and (D) only  

Ans.

(1)

(A)(D)(E) Starch – Starch is the main storage polysaccharide of plants. Amylose and Amylopectin are two components of starch. Amylose is a long unbranched chain with 200–1000 α-D-(+)-glucose units held together by C1–C4 glycosidic linkage. Amylopectin is a branched chain polymer of α-D-glucose units in which chain is formed by C1–C4 glycosidic linkage whereas branching occurs by C1–C6 glycosidic linkage. Hence hydrolysis of starch/amylose/amylopectin gives α-D-(+)-glucose.

(B) Sucrose (cane sugar) consists of a glycosidic linkage between C1 of α-D-glucose and C2 of β-D-fructose. Hence on hydrolysis it gives equal amount of glucose and fructose.

(C) Lactose (milk sugar): It is composed of β-D-galactose and β-D-glucose. The linkage is between C1 of galactose and C4 of glucose. Hence on hydrolysis it gives galactose and glucose.