• 072920 77839
  • info@smartachievers.in
Menu
Back
  • JEE ADVANCE
  • JEE MAIN
  • NEET
  • BITSAT
  • CBSE BOARD
  • UP BOARD
  • CUET
  • Other Competitive Exams
JEE ADVANCE
  • CLASS XI - XII
  • CRASH COURSE
JEE MAIN
  • CLASS XI - XII
  • CRASH COURSE
CRASH COURSE
NEET
  • CLASS XI - XII
  • CRASH COURSE
BITSAT
  • CLASS XI - XII
CBSE BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
  • CLASS VI
  • CLASS VII
  • CLASS VIII
UP BOARD
  • CLASS IX
  • CLASS X
  • CLASS XI
  • CLASS XII
CUET
  • CRASH COURSE
Other Competitive Exams
  • NDA
Courses


Solution


Q.

Given alongside is a geometrical shape.
C is centre of semicircle with radius BC=21 cm.
△ABC is isosceles triangle. (Use π=3.14)

Which of the following statements are correct

(i) Area of triangle ABC outside circular region = 47.4075 cm²

(ii) Area of sector CBD = 276 cm²

(iii) Angle of sector CBD = 45°

(iv) Areaof∆ABC=220.5cm²

Choose the correct option from the following
1 (i), (iii) and (iv)  
2 (i) and (ii)
 
3 (i) and (iii)  
4 (iii) and (iv)  

Ans.

(1)

Since∆ABC is isoscelesAB=BC=21 cmArea of ∆ABC:=12×AB×BC=12×(21)2=220.5 cm2∴Statement (iv) is correct.∆ABC is isosceles with∠B=90°So, the other angles each measure 45°.⇒Angle of sector CBD=45°∴Statement (iii) is correct.Area of sector CBD=θ360°×πr2=45360×3.14×21×21=173.0925 cm2∴Statement (ii) is incorrect.Area of triangle outside circular region=Area of ∆ABC-Area of sector CBD=220.5-173.0925=47.4075 cm2∴Statement (i) is correct.