Given, (A) 2 CO ( g ) + O 2 ( g ) 2 CO 2 ( g ) H 1= - x?kJ mol - 1 (B) C ( graphite ) + O 2 ( g ) 2 CO 2 ( g ) H 2 = - y?kJ mol - 1 The H for the reaction C ( graphite ) + 1 2 O 2 ( g ) CO ( g ) is [2023]

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Solution

Q.
Given,

(A) $2 CO (g) + O_{2} (g) \to 2 {CO}_{2} (g)$ $Δ H_{1}^{θ} = - {x kJ mol}^{- 1}$

(B) $C (graphite) + O_{2} (g) \to 2 {CO}_{2} (g)$ $Δ H_{2}^{θ} = - {y kJ mol}^{- 1}$

The $Δ H^{θ}$ for the reaction $C (graphite) + \frac{1}{2} O_{2} (g) \to CO (g)$ is [2023]

1 $\frac{x + 2 y}{2}$

2 $\frac{x - 2 y}{2}$

3 $\frac{2 x - y}{2}$

4 $2 y - x$

Ans.
(2)

$From equation (B) - \frac{(A)}{2} = target equation$

$C (graphite) + O_{2} (g) ⟶ C O_{2} (g); Δ H_{2}^{0} = - y kJ/mol$

$[2 C O_{2} (g) ⟶ 2 C O (g) + O_{2} (g)] \times \frac{1}{2}; Δ H_{1} = - x kJ/mol \times \frac{1}{2}$

$C (graphite) + \frac{1}{2} O_{2} (g) ⟶ C O (g)$

So, $ΔH for required equation = - y - (\frac{- x}{2}) = - y + \frac{x}{2}$

$= \frac{x - 2 y}{2} kJ/mol$

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