From the v-t graph shown, the ratio of distance to displacement in 25 s of motion. [2023]

STUDY MATERIALS
COURSES
MORE
SUCCESS STORY
ADMISSION
STORE

Back

JEE ADVANCE

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

JEE MAIN

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

NEET

CLASS XI - XII
CRASH COURSE

CLASS XI - XII

CRASH COURSE

BITSAT

CLASS XI - XII

CLASS XI - XII

CBSE BOARD

CLASS IX

CLASS X

CLASS XI

CLASS XII

CLASS VI

CLASS VII

CLASS VIII

UP BOARD

CLASS IX
CLASS X
CLASS XI
CLASS XII

CLASS IX

CLASS X

CLASS XI

CLASS XII

CUET

CRASH COURSE

CRASH COURSE

Courses

CLASSROOM COURSES
ONLINE COURSES

ONLINE COURSES

More

Solution

Q.
From the $v - t$ graph shown, the ratio of distance to displacement in 25 s of motion. [2023]

1 $\frac{3}{5}$

2 $\frac{1}{2}$

3 $\frac{5}{3}$

4 $1$

Ans.
(3)

$Area under the graph from t = 0 to t = 20 s = 200 m$

$Area under the graph from t = 20 to t = 25 s = 50 m$

$So distance covered = (200 + 50) m = 250 m$

$Displacement = (200 - 50) m = 150 m$

$\frac{250}{150} = \frac{5}{3}$

Want Us to Email you About Special Offers & Updates?